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What is the maximum wind velocity for a 45-degree crosswind if the maximum crosswind component for the airplane is 25 knots?

A) 25 knots
B) 35 knots
C) 31 knots
D) Not enough information provided

1 Answer

5 votes

Final answer:

The maximum wind velocity for a 45-degree crosswind is approximately 35 knots. To determine the maximum wind velocity for a 45-degree crosswind, the crosswind component is divided by the cosine of 45 degrees, yielding a value close to 35 knots.

Step-by-step explanation:

The maximum wind velocity for a 45-degree crosswind can be found using trigonometry. We can use the concept of crosswind components to solve this problem. The crosswind component is the force of the wind acting perpendicular to the direction of the airplane. In this case, the maximum crosswind component is given as 25 knots.

To find the maximum wind velocity, we can use the sine function. The sine of a 45-degree angle is equal to the ratio of the opposite side to the hypotenuse. In this case, the opposite side is the crosswind component of 25 knots and the hypotenuse is the maximum wind velocity we want to find.

Using the sine function, we have:

sin(45) = crosswind component / maximum wind velocity

Substituting the given values, we get:

sin(45) = 25 / maximum wind velocity

Now, we can calculate the maximum wind velocity:

maximum wind velocity = 25 / sin(45)

Simplifying the expression, we find that the maximum wind velocity is approximately 35 knots.

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