Final answer:
The code as presented will result in a syntax error due to empty parentheses. For a successful check, the code should include the string variable 'name' within the parentheses. Corrected, it would then output True, since 'y' is present in 'SKYE HOMSI'.
Step-by-step explanation:
There are a couple of issues in the provided code snippet. Let's correct them and analyze the output:
name = "SKYE HOMSI"
print("y" in name.lower())
Here's the corrected code. I've added the variable name and converted it to lowercase using the lower() method before checking if "y" is in it.
Now, let's break down the code:
name.lower(): This converts the string "SKYE HOMSI" to lowercase, resulting in "skye homsi".
"y" in name.lower(): This checks if the character "y" is present in the lowercase version of the name. In this case, it is present.
The code first initializes a variable name with the value "SKYE HOMSI". To check if the character "y" is present in the name, the code uses the in keyword and the lower() method to ensure case-insensitive matching. The lower() method converts the string to lowercase, resulting in "skye homsi". The print statement then outputs whether "y" is present in the lowercase version of the name.
As "y" is indeed present in "skye homsi", the output of the code will be True. It's important to note that the in operator returns a boolean value (True or False) based on whether the specified element is found in the given sequence. In this case, the sequence is the lowercase version of the name, and the specified element is the character "y".