Question

2. The boiling point of a solution containing 6.4 g of the hormone adrenaline in 360 g of

CCl4 is 0.49 K higher than the boiling point of pure CC14. Calculate the molar mass of
adrenaline. (K = 5.02 kg K/mol).​

Answer 1

MM = 182.13g/mol

Step-by-step explanation:

Hello!

In this case, since the boiling point elevation is computed via:

`\Delta Tb=i*m*K`

Thus, since adrenaline is nonionizing, we can compute the molality at first instance:

`m=(\Delta Tb)/(i*K)=(0.49K)/(1*5.02kg(K)/(mol) ) \\\\m=0.0976mol/kg`

Now, we compute the the moles of adrenaline in 360 g (0.360 kg) of CCl4:

`n=0.0976mol/kg*0.360kg\\\\n=0.0351mol`

Finally, the molar mass:

`MM=(6.4g)/(0.0351mol)\\\\MM=182.13g/mol`

Best regards!