Final answer:
The load in the member AB is 174.83 N. Therefore, the load in the member AB is 17.84 kg times the acceleration due to gravity (9.8 m/s²), which equals to 174.83 N.
Step-by-step explanation:
When a traffic light is suspended from two wires, the tension in each wire can be calculated using the concepts of equilibrium.
We can assume that the traffic light is in equilibrium, which means that the sum of the forces acting on it is zero.
In this case, the tension in the cable AB (load) is equal to the weight of the traffic light, which is given as 17.84 kg.
Therefore, the load in the member AB is 17.84 kg times the acceleration due to gravity (9.8 m/s²), which equals to 174.83 N.