Final answer:
To heat 10 grams of steam by 100°C, 18700 joules of energy must be absorbed, calculated using the specific heat of steam (1.87 J/g°C) and the mass-temperature change product.
Step-by-step explanation:
To determine the amount of energy absorbed by the steam, we use the specific heat capacity formula. The formula to calculate heat absorbed, often represented as q, is q = Cp × m × ΔT, where Cp is the specific heat of the substance, m is the mass, and ΔT is the change in temperature.
In this scenario, the mass m of the steam is 10 grams, the specific heat Cp of steam is 1.87 J/(g°C), and the temperature increase ΔT is 100°C. Plugging these values into the formula gives us:
q = (1.87 J/g°C) × (10 g) × (100°C)
q = 187 J/g × 100
q = 18700 J
Therefore, 18700 joules of heat must be absorbed by 10 grams of steam to raise its temperature by 100°C.