Question

One number is 3 less than 4 times a second number. The difference of the first number and twice the second number is 7. What are the two numbers?

Answer 1

The two numbers are 17 and 5.

Step-by-step explanation:

Let's assume the first number is represented by x, and the second number is represented by y.

We can set up two equations based on the given information:

x = 4y - 3

x - 2y = 7

Substituting the value of x from the first equation into the second equation, we get:

4y - 3 - 2y = 7

Combining like terms, we have:

2y - 3 = 7

Adding 3 to both sides of the equation, we get:

2y = 10

Dividing both sides by 2, we find:

y = 5

Substituting the value of y into the first equation, we get:

x = 4(5) - 3 = 20 - 3 = 17

Therefore, the two numbers are 17 and 5.

Answer 2

atq= let no.be x and y

x= 4y-3.......(1)

x-2y=7....(2)

subtracting both eqn

x-x+2y=4y-3-7

2y=4y-10

-2y= -10

y=5 ........second no.

first no...x=7+2y=7+10=17.......first no....