To draw the Bode diagram for G(S)=20/S(S+1)(S+10), the x-axis generally starts a decade below the smallest corner frequency and ends a decade above the highest corner frequency, which for this function would be approximately 0.01 rad/s to 1000 rad/s.
The student has asked about determining the limit values on the x-axis to draw the Bode diagram of the given system with an open-loop transfer function G(S) = 20/S(S+1)(S+10). The Bode plot consists of a magnitude plot and a phase plot, typically using a logarithmic scale for frequency on the x-axis.
The limit values would generally span from a frequency value just below the smallest corner frequency (which is determined by the poles and zeros of the transfer function) to a frequency value that is significantly higher than the highest corner frequency. In this case, the system has three poles: at S=0, S=-1, and S=-10.
Typically, we would start at a frequency that is one decade lower than the lowest corner frequency, which is 0.1 rad/s given that the first pole is at 0. Therefore, the starting point could be around 0.01 rad/s. We would end at a frequency that is at least one decade higher than the highest corner frequency, which is 100 rad/s, given the last pole at 10 rad/s. Therefore, the endpoint could be around 1000 rad/s. These values provide enough range to capture the behavior of the transfer function over all relevant frequencies.
So, to draw the Bode diagram for this system, the limit values on the x-axis should extend from approximately 0.01 rad/s to 1000 rad/s.