Question

A steady, two-dimensional velocity field is given by v-(u, u) := (-0.781-3.25x)it (-3.54 + 3.25y)/ 4-5 Calculate the location of the stagnation point.

Answer 1

The location of the stagnation point is (-0.24, 1.09).

Step-by-step explanation:

The location of the stagnation point can be found by setting the x and y components of the velocity field equal to zero and solving for the corresponding values of x and y.

For the x component: -0.781 - 3.25x = 0

Solving for x, we get x = -0.781/3.25 = -0.24

For the y component: -3.54 + 3.25y = 0

Solving for y, we get y = 3.54/3.25 = 1.09

Therefore, the location of the stagnation point is (-0.24, 1.09).