Question

Butane gas and 200% theoretical air, both at 25°C, enter a steady flow combustor. The products of combustion exits at 1000 K. Calculate the heat transfer from the combustor per kmol of butane burned (to 4 significant digits). The unit is kJ/kmol butane.

Answer 1

To calculate the heat transfer from the combustor per kmol of butane burned, we can use the enthalpy of combustion of butane and the enthalpy change of formation of the products of combustion.

Step-by-step explanation:

To calculate the heat transfer from the combustor per kmol of butane burned, we can use the enthalpy of combustion of butane and the enthalpy change of formation of the products of combustion. The enthalpy of combustion of butane is the heat released when 1 mol of butane is burned to form CO₂(g) and H₂O(g). The enthalpy of combustion is equal to the enthalpy change of formation of the products minus the enthalpy change of formation of butane. Given that the enthalpy of formation of butane is -126 kJ/mol, we can use this information to calculate the heat transfer per kmol of butane burned.