Question

The pressure and temperature of N² and gas drops from 303kPa at 300K to 202²kPa at -73°C. If the initial volume is 2L, find the new volume.

Answer 1

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Step-by-step explanation:

Using the combined gas law equation as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to this question;

T1 = 300K

T2 = -73 + 273 = 200K

P1 = 303kPa

P2 = 202kPa

V1 = 2L

V2 = ?

Using the above formula:

303 × 2/300 = 202 × V2/200

606/300 = 202V2/200

Cross multiply;

606 × 200 = 300 × 202V2

121200 = 60600V2

V2 = 121200/60600

V2 = 2L

The new volume is 2L