Final answer:
To minimize the cost for Ahmet's fertilizer use, we set up an LP with two variables, x and y, representing the number of bags of Fertilizer A and B, respectively. The objective function is to minimize Z = 10x + 20y, subject to the constraints based on corn and wheat production and the limit on Fertilizer B. The problem can be solved graphically by finding the optimal corner point in the feasible region defined by the constraints.
Step-by-step explanation:
To help Ahmet minimize the total cost of using fertilizers while meeting his production targets, we can set up a Linear Programming (LP) problem with two decision variables: the number of bags of Fertilizer A (let's call this x) and the number of bags of Fertilizer B (let's call this y).
The objective function, which we want to minimize, represents the total cost of the fertilizers:
Minimize Z = 10x + 20y
The constraints based on the required production are:
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- 4x + 6y ≥ 72 (for corn)
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- 5x + 4y ≥ 80 (for wheat)
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- y ≤ 10 (limit on Fertilizer B due to environmental regulations)
We also have the non-negativity constraints:
To graphically solve the LP, we plot the constraints on a coordinate system where x is on the horizontal axis and y is on the vertical axis. The feasible region is determined by the area that satisfies all constraints, and the optimal solution lies at a corner point of this region. By examining the cost function at these corner points, we find the point that minimizes the total cost.