Final answer:
The quadratic term in the equation y = 3x²+6x-1 is 3x², the linear term is 6x, and the constant term is -1.
Step-by-step explanation:
The question involves identifying different terms in the quadratic equation y = 3x²+6x-1. In any quadratic equation of the form ax² + bx + c = 0, 'a' represents the coefficient of the quadratic term, 'b' represents the coefficient of the linear term, and 'c' represents the constant term.
In the given equation, 3x² is the quadratic term, 6x is the linear term, and -1 is the constant term. The quadratic formula used for solving such equations is x = (-b ± √(b² - 4ac))/(2a), where 'a', 'b', and 'c' are the coefficients as described above.
The quadratic term in the given expression is 3x², as it is the term with a variable raised to the power of 2.
The linear term in the given expression is 6x, as it is the term with a variable raised to the power of 1.
The constant term in the given expression is -1, as it is the term with a variable raised to the power of 0.