Final answer:
The new temperature needed to increase the volume of the fluorine gas to 8250 mL is 332.65 K. This result is based on applying Charles's law, which relates volume and temperature of a gas under constant pressure.
Step-by-step explanation:
The task is to find the new temperature to which fluorine gas should be increased to achieve a volume of 8250 mL from an initial volume of 6200 mL at 250 K. This scenario can be analyzed through Charles's law, which states that the volume of a gas is directly proportional to its absolute temperature when the pressure and the amount of gas are held constant. The formula for Charles's law is V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.
Using the provided values, the initial volume (V1) is 6200 mL, and the initial temperature (T1) is 250 K. The final volume (V2) is 8250 mL, and we are solving for the final temperature (T2). By rearranging the formula, we get T2 = (V2/V1) * T1.
Plugging in the values, we get T2 = (8250 mL / 6200 mL) * 250 K = 1.3306 * 250 K = 332.65 K as the final temperature.