Answer:
- f(x) = 6ln(8) -6ln(x)
- f'(x) = -6/x
Explanation:
You want to rewrite f(x) and differentiate it for f(x) = 6·ln(8/x).
Rules of logarithms
The log of a ratio is the difference of logs:
ln(a/b) = ln(a) -ln(b)
Application
Using this to rewrite f(x), we have ...
f(x) = 6ln(8/x) = 6(ln(8) -ln(x))
f(x) = 6·ln(8) -6·ln(x)
Derivative
The derivative of the constant is zero, so ...
f'(x) = -6/x