Question

If you have a set of seven heuristics, how many unique pairs of two heuristics can be made out of these?

A) 14
B) 21
C) 28
D) 35

Answer 1

The correct answer is option B, which represents that 21 unique pairs can be made from a set of seven heuristics using the combination formula C(n, k) = n! / (k!(n-k)!), with n=7 and k=2.

Step-by-step explanation:

The correct answer is option B. When looking to make pairs from a set of seven heuristics, we are essentially looking for the number of combinations that can be formed by choosing 2 heuristics out of 7 without considering the order. This can be calculated using the combination formula which is:

C(n, k) = n! / (k!(n-k)!)

For our specific case, n=7 and k=2, so the calculation would be:

C(7, 2) = 7! / (2!(7-2)!) = (7×6×5×4×3×2×1) / ((2×1)(5×4×3×2×1)) = 21

Therefore, 21 unique pairs of two heuristics can be made from a set of seven heuristics.