Final answer:
The final displayed value of x after the execution of the code will be -12. The code iteratively increases and changes the sign of x, resulting in this value after several operations governed by integer arithmetic rules.
Step-by-step explanation:
The code provided is a nested loop programming concept that modifies the value of variable x in each iteration. Initially, x is set to 0, and the variable a is set to 3, denoting the number of times the outer loop will run. The variable k is set to 4, representing the number of times the inner loop will run. Inside the inner loop, the value of x is incremented by the value of a, which happens k times (4 times). Hence, after the inner loop, x will be x + a*4. After the inner loop concludes, x is then multiplied by -1 in the outer loop. As this pattern repeats for a times (3 times), with integer arithmetic rules, the pattern of sign change will affect the final result.
To calculate the final value of x, after the first iteration of the outer loop, x becomes 3*4 = 12, and then it is multiplied by -1, which results in x = -12. In the second iteration, since x is now negative, when we add 3*4 again, then multiply by -1, x becomes positive again (12). Finally, in the third iteration, after adding and then multiplying by -1, x returns to being negative, resulting in -12. Therefore, the final display of x after the completion of the loops would be -12.