Final answer:
The derivative of (sec^-1u) can be found using the chain rule and the derivative of the inverse of the secant function. The result is 1 / (u * sqrt(u^2 - 1)).
Step-by-step explanation:
The derivative of (sec^-1u) can be found using the chain rule of differentiation and the derivative of the inverse of the secant function.
- Let y = sec^-1(u).
- Then, sec(y) = u.
- Take the derivative of both sides with respect to u:
- sec(y) * tan(y) * dy/du = 1.
- Substitute sec(y) with u:
- u * tan(y) * dy/du = 1.
- Solve for dy/du:
- dy/du = 1 / (u * tan(y)).
- Finally, substitute tan(y) with sqrt(u^2 - 1):
- dy/du = 1 / (u * sqrt(u^2 - 1)).
Therefore, the derivative of (sec^-1u) is 1 / (u * sqrt(u^2 - 1)).