Question

Two bars are in contact. All sides of the bars are insulated in such a way that heat flow is one dimensional. Heat flux, temperatures at the end of each bar, and the thermal conductivities of the bars are given as follows. q′′=6.2 W/m2TA=52.9∘C,xA=0.05,kA=0.1 W/mKTB=33.7∘C,xB=0.04,kB=0.2 W/mK

Answer 1

The question pertains to the calculation of heat conduction in a two-bar system with different thermal conductivities and temperatures, based on the heat flux and the physical properties of the materials.

Step-by-step explanation:

The question presented involves the concept of heat conduction through two bars with different thermal conductivities and at different temperatures. The rate of heat transfer (Q/t) is important in calculating the temperature distribution and the heat flow in such problems. According to Fourier's law, for one-dimensional heat transfer, the heat flux (q'') can be described by the equation q'' = -kA(T2 - T1) / d, where 'k' is the thermal conductivity of the material, 'A' is its cross-sectional area, 'd' is the material's thickness, and '(T2 - T1)' represents the temperature difference across the slab. To solve these types of problems, one should generally identify all knowns, express them in SI units, and create equations that reflect the systems' energy balance.