Final answer:
The solutions to the equation x²-4x-5=0 can be found by using the quadratic formula. The solutions are x = 5 and x = -1.
Step-by-step explanation:
The solutions to the equation x²-4x-5=0 can be found by using the quadratic formula. For an equation of the form ax²+bx+c=0, the solutions are given by:
x = (-b ± √(b²-4ac)) / (2a)
In this case, a = 1, b = -4, and c = -5, so substituting these values into the formula, we get:
x = (-(-4) ± √((-4)²-4(1)(-5))) / (2(1))
Simplifying further, we have:
x = (4 ± √(16+20)) / 2
x = (4 ± √36) / 2
x = (4 ± 6) / 2
Therefore, the solutions are x = 5 and x = -1.