Final answer:
The shaft tolerance limits should be 7.995 to 8.000 mm to achieve the required maximum clearance of .002 mm and incorporate the allowance of –.005 mm. This results in a transition fit, which can be a tight transition fit.
Step-by-step explanation:
To determine the tolerance limits of the shaft that correspond to the given tolerance limits of the hole, we need to consider both the maximum clearance and the allowance. The hole tolerance limits are given as 8.001 and 8.000 mm.
By definition, clearance is the difference between the largest possible hole and the smallest possible shaft. The required maximum clearance is .002 mm. Allowance is the intentional difference between the maximum material limits of the hole and the shaft. Here, the allowance is given as –.005 mm, which indicates an interference or transition fit because it's negative.
Since the largest size of the hole is 8.001 mm, to achieve the maximum clearance of .002 mm, the maximum size of the shaft should be:
8.001 mm (hole max size) - .002 mm (max clearance) = 8.000 mm (shaft max size)
To include the allowance of -.005 mm, the minimum size of the shaft should be:
8.000 mm (hole max size) - .005 mm (allowance) = 7.995 mm (shaft min size)
Therefore, the shaft tolerance limits need to be 7.995 to 8.000 mm.
Bearing in mind the negative allowance and the required maximum clearance, the type of fit implied here appears to be a transition fit, possibly a tight transition fit because it allows for a small amount of either clearance or interference.