Question

A circular cylinder 50 m long having diameter 0.05 m is buried at the centre of a concrete block having a square cross-sectional area A = 4 m2. If the thermal conductivity of the concrete block is & = 0.01W /mK, determine the heat transfer rate if the boundary of the block are at a temperature of 300 K and the temperature of the cylinder is 350 K.

Answer 1

The heat transfer rate can be calculated using the formula: Rate of heat transfer (Q/t) = k * A * (T2 - T1) / d

Step-by-step explanation:

The rate of heat transfer, or the heat transfer rate, is determined using the formula:

Rate of heat transfer (Q/t) = k * A * (T2 - T1) / d

where Q/t is the rate of heat transfer in watts, k is the thermal conductivity of the material, A is the surface area, T2 and T1 are the temperatures of the boundary and the cylinder respectively, and d is the thickness of the material.

Plugging in the given values: k = 0.01 W/mK, A = 4m^2, T2 = 300K, T1 = 350K, and d = 0.05m, we get:

Q/t = 0.01 * 4 * (300 - 350) / 0.05.

Now we can calculate the heat transfer rate using the given values.