Question

For a 2:1 cylinder in a regeneration circuit, how fast does it extend (in ft/min or in/min)? The cylinder has a rod area of 2in² and the system delivers 12gpm. (Include the correct units with your answer)

Answer 1

The cylinder extends at a speed of 1386 in/min, which equates to 115.5 ft/min when using the given flow rate of 12 GPM and a rod area of 2 in².

Step-by-step explanation:

To calculate the cylinder extension speed, we need to apply the formula for the volumetric flow rate in hydraulic systems, which is Flow Rate (Q) = Area (A) × Velocity (V). We rearrange this formula to solve for velocity (or speed of extension in this case), V = Q / A. Since the system delivers 12 GPM (gallons per minute), we first need to convert GPM to cubic inches per minute because the rod area is given in square inches. There are 231 cubic inches in a gallon, so Q = 12 GPM × 231 in³/Gal = 2772 in³/min.

Given the rod area A = 2 in², the velocity of the cylinder extension V = 2772 in³/min / 2 in² = 1386 in/min (inches per minute). To convert this to feet per minute, we divide by 12 (the number of inches in a foot), resulting in V = 1386 in/min ÷ 12 in/ft = 115.5 ft/min.