Final answer:
To calculate the amount of heat required to pass 2 tons of water per hour from 0°C to 200°C, we need to consider the different stages of the heating process: heating the ice, melting the ice, heating the water, boiling the water, and heating the steam. Adding up all the individual heats will give us the total amount of heat required.
Step-by-step explanation:
To calculate the amount of heat required to pass 2 tons (2000 kg) of water per hour from 0°C (ice) to 200°C (steam) at 1 atm pressure, we need to consider the different stages of the heating process:
- First, we need to heat the ice from -15°C to 0°C. This requires the heat of fusion, which is given by the equation Q₁ = m₁ * L_f, where m₁ is the mass of ice and L_f is the heat of fusion of ice.
- Next, we need to melt the ice at 0°C. This requires the heat of fusion, which is given by the equation Q₂ = m₂ * L_f, where m₂ is the mass of melted ice.
- Then, we need to heat the water from 0°C to 100°C.
- This requires the specific heat capacity of water, which is given by the equation Q₃ = m₃ * C_w * ΔT, where m₃ is the mass of water, C_w is the specific heat capacity of water, and ΔT is the change in temperature.
- After that, we need to boil the water at 100°C.
- This requires the heat of vaporization, which is given by the equation Q₄ = m₄ * L_v, where m₄ is the mass of water vapor and L_v is the heat of vaporization of water.
- Finally, we need to heat the steam from 100°C to 200°C.
- This requires the specific heat capacity of steam, which is given by the equation Q₅ = m₅ * C_s * ΔT, where m₅ is the mass of steam, C_s is the specific heat capacity of steam, and ΔT is the change in temperature.
To calculate the total heat required, we add up all the individual heats: Q_total = Q₁ + Q₂ + Q₃ + Q₄ + Q₅.