212k views
1 vote
A: What is the maximum velocity, umax, at the outlet

section?
B: What is the momentum (flux) correction coefficient at the
outlet section?
C: If the frictional force on the tunnel walls is assumed to
An axisymmetric body (somewhat like a torpedo) is tested in a wind tunnel of circular cross-section with air as fluid.

1 Answer

0 votes

Final answer:

The maximum velocity at the outlet section can be determined using the principle of conservation of mass. The momentum correction coefficient at the outlet section accounts for the change in velocity and pressure. The specific values depend on the specific conditions and geometry.

Step-by-step explanation:

The maximum velocity at the outlet section of a fluid flow can be determined using the principle of conservation of mass. The mass flow rate at the inlet is equal to the mass flow rate at the outlet, which can be expressed as ρ₁A₁V₁ = ρ₂A₂V₂, where ρ is the density, A is the cross-sectional area, and V is the velocity. By rearranging the equation, you can solve for the maximum velocity (umax) at the outlet section.

The momentum correction coefficient at the outlet section is a dimensionless factor that accounts for the change in velocity and pressure across the section. It can be calculated using the equation C = (A₁/A₂) * (V₂/V₁), where A₁ and A₂ are the cross-sectional areas at the inlet and outlet, and V₁ and V₂ are the corresponding velocities.

However, it should be noted that the specific values for umax and the momentum correction coefficient would depend on the specific conditions and geometry of the wind tunnel and the object being tested.

User Vincentius
by
8.8k points