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what is the molarity of a solution containing 26.6 g of c₆h₁₂o₆ in 3.5 l of solution? the molecular weight of glucose is 180.16 g/mol.

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Final answer:

To find the molarity of the glucose solution, divide the mass of glucose (26.6 g) by the molar mass (180.16 g/mol) to get the number of moles, then divide by the volume of the solution in liters (3.5 L).

Step-by-step explanation:

The molarity of a solution is calculated by dividing the number of moles of solute by the volume of solution in liters. First, you need to find the number of moles of glucose, which is done by dividing the mass of glucose (26.6 g) by its molar mass (180.16 g/mol). Then, divide the number of moles by the volume of the solution in liters (3.5 L) to find the molarity.

Calculation:
Number of moles of C₆H₁₂O₆ = 26.6 g / 180.16 g/mol = 0.1477 moles
Molarity (M) = Number of moles / Volume in liters = 0.1477 moles / 3.5 L = 0.0422 M

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