Question

how many mole of co₂ is produced at stp from 4.00 g of o₂ and 12.0 l of acetylene at stp? include the abbreviated unit for credit.

Answer 1

To calculate the number of moles of CO₂ produced at STP, convert the given quantities to moles and use the stoichiometry of the balanced equation.

Step-by-step explanation:

To calculate the number of moles of CO₂ produced, we need to determine the limiting reactant. The balanced equation is:

2 C₂H₂ (g) + 5 O₂ (g) → 4 CO₂ (g) + 2 H₂O (g)

First, we need to convert the given quantities to moles:

4.00 g O₂ × (1 mol O₂ / 32.00 g O₂) = 0.125 mol O₂

12.0 L acetylene × (1 mol acetylene / 22.414 L acetylene) = 0.536 mol acetylene

From the balanced equation, we can see that the ratio of O₂ to CO₂ is 5:4. Therefore, the number of moles of CO₂ produced is:

0.125 mol O₂ × (4 mol CO₂ / 5 mol O₂) = 0.100 mol CO₂

So, 0.100 mole of CO₂ is produced at STP from 4.00 g of O₂ and 12.0 L of acetylene.