Question

a cubic box with sides of 20 cm is closed and sealed in tucson where the atmosphericpressure is 930 mbar. it is driven to the top of mount lemmon where the pressure is reduced to745 mbar. what is the net force on the lid of the box due to the air?

Answer 1

The net force on the lid of the box due to the air pressure difference is 74000 cm²·mbar. The net force on the lid of the box due to the air pressure difference can be calculated using the pressure difference and the area of the lid.

Step-by-step explanation:

To calculate the net force on the lid of the box due to the air pressure difference, we need to consider the difference in atmospheric pressure at Tucson and Mount Lemmon.

Given that the atmospheric pressure in Tucson is 930 mbar and in Mount Lemmon is 745 mbar, we can calculate the pressure difference:

Pressure difference = Atmospheric pressure at Tucson - Atmospheric pressure at Mount Lemmon

Pressure difference = 930 mbar - 745 mbar

= 185 mbar

Now, to calculate the net force on the lid of the box, we can use the formula:

Net force = Pressure difference × Area of the lid

The area of the lid can be calculated using the formula:

Area = Side length × Side length

= 20 cm × 20 cm

= 400 cm²

Now, substituting the values into the formula, we get:

Net force = 185 mbar × 400 cm²

= 74000 cm²·mbar

So, the net force on the lid of the box due to the air pressure difference is 74000 cm²·mbar.