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An industrial-scale process for making acetylene (C2H2) consists of the following sequence of operations:

1. CaCO₃ → Cao + CO₂
Iimestone lime carbon dioxide

2. CaO + 3 C → CaC₂ + CO
calcium carbide carbon monoxide
3. CaC₂ + 2 H₂O → Ca(OH)₂ + C₂H₂
calcium hydroxide acetylene

What is the percentage yield of the overall process if 2.37 metric tons of C2H2 is produced from 10.0 metric tons of limestone (CaCO 3) ? (1 metric ton ≡1000kg ) %

1 Answer

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The percentage yield of the overall process is 91.20%. This means that 91.20% of the expected amount of acetylene was obtained from the given amount of limestone.

To calculate the percentage yield of the overall process, we need to determine the amount of acetylene (C2H2) that can be produced from the given amount of limestone (CaCO3) and compare it to the actual amount obtained.

Step 1: Calculate the molar mass of CaCO3

The molar mass of CaCO3 is 100.09 g/mol (40.08 g/mol for Ca + 12.01 g/mol for C + 3 * 16.00 g/mol for O)

Step 2: Convert the mass of limestone to moles

10.0 metric tons of limestone is equal to 10,000 kg.

10,000 kg * (1 mol/100.09 g) = 99.98 mol of CaCO3

Step 3: Calculate the theoretical yield of C2H2

From the balanced equation, we can see that 1 mol of CaCO3 produces 1 mol of C2H2.

Therefore, the theoretical yield of C2H2 is also 99.98 mol.

Step 4: Convert the theoretical yield to mass

99.98 mol * (26.04 g/mol) = 2,599.40 g

Step 5: Convert the mass to metric tons

2,599.40 g = 2.5994 metric tons

Step 6: Calculate the percentage yield

Percentage Yield = (Actual Yield / Theoretical Yield) * 100%

Percentage Yield = (2.37 metric tons / 2.5994 metric tons) * 100%

Percentage Yield = 91.20%

User Abhinandan Sahgal
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