The complex ion [Fe(NH₃)₆]²⁺ has four unpaired electrons. Option 3) 4 is the correct answer.
To determine the number of unpaired electrons in the complex ion [Fe(NH₃)₆]²⁺, we need to consider the electronic configuration of the central iron (Fe) atom and the ligands (NH₃) surrounding it.
Iron (Fe) has an atomic number of 26, indicating that it has 26 electrons. The electronic configuration of Fe in its ground state is [Ar] 3d⁶ 4s². In the complex ion, Fe is in the +2 oxidation state, which means it loses two electrons from its outermost 4s² orbital.
Now, let's consider the ligands NH₃. Each NH₃ ligand has a lone pair of electrons, which can form a coordinate bond with the Fe ion. Since there are six NH₃ ligands in the complex, we have a total of six lone pairs available for bonding.
In a complex, the central metal ion can use its d orbitals to form bonding and non-bonding electron pairs. The number of unpaired electrons in the complex is determined by the number of d orbitals that are not involved in bonding with the ligands.
In the case of [Fe(NH₃)₆]²⁺, the Fe²⁺ ion has four unpaired electrons. This is because the Fe²⁺ ion has a d⁶ electronic configuration, and the six available d orbitals are occupied by six electrons from the NH₃ ligands, leaving four unpaired electrons.