To determine the height from which the ball is thrown, we can use the horizontal distance traveled and the time of flight. In this case, the height is found to be 122.5 meters.
To determine the height from which the ball is thrown, we need to consider the horizontal distance the ball travels and the time it takes to reach the ground.
First, we can find the time of flight using the formula t = d/v, where d is the horizontal distance and v is the initial horizontal component of the velocity. In this case, d = 100.0 m and v = 20.0 m/s. So, t = 100.0 m / 20.0 m/s = 5.0 s.
Next, we can find the time it takes for the ball to fall to the ground using the formula h = 1/2 g t^2, where h is the height of the building, g is the acceleration due to gravity (9.8 m/s^2), and t is the time of flight. In this case, h = ? (what we're trying to find), g = 9.8 m/s^2, and t = 5.0 s. Rearranging the formula, we get h = 1/2 gt^2 = 1/2 * 9.8 m/s^2 * (5.0 s)^2 = 122.5 m.
Therefore, the height from which the ball is thrown is 122.5 meters.