For the first question, the image distance is 6.67 cm. For the second question, the image distance is 4.44 cm and the magnification is -0.222. For the third question, the image distance is -92.5cm, the power of the corrective lens needed is -1.09 diopters, and the corrective lens needed is converging.
Step-by-step explanation:
To determine the size of the image formed by the lens system, we can use the thin lens equation 1/f = 1/do + 1/di, where f is the focal length of the lens, do is the object distance, and di is the image distance.
For the first question, the lenses have a focal length of 5 cm. The object distance (do) is 10 cm. Plugging these values into the equation, we get 1/5 = 1/10 + 1/di. Solving for di, we find that the image distance is 6.67 cm.
For the second question, the lenses have a focal length of 5 cm and are spaced 20 cm apart. The object distance (do) is 20 cm. Plugging these values into the equation, we get 1/5 = 1/20 + 1/di. Solving for di, we find that the image distance is 4.44 cm. The magnification can be calculated using the formula m = -di/do. Plugging in the values, we find that the magnification is -0.222.
For the third question, Jane's near point is 125 cm and the computer screen is 40 cm away from her eye. The object distance (do) is 125-40 = 85 cm. The image distance can be calculated using the formula 1/f = 1/do + 1/di. Plugging in the values, we find that the image distance is -92.5 cm. The power of the corrective lens can be calculated using the formula P = 1/f. Plugging in the value of f, we find that the power of the corrective lens needed is -1.09 diopters. The corrective lens needed is converging.
The probable question can be: 1) How large does a 5 mm insect appear when viewed with a system of two identical lenses of focal length 5 cm separated by a distance 12 cm if the insect is 10 cm from the first lens? mm 2) Three converging lenses of focal length 5 cm are arranged with a spacing of 20 cm between them, and are used to image an insect 20 cm to the left of the first lens. a) Where is the image with respect to the third lens? cm b) left or right What is the magnification of the image? cm 3) Jane has a near point of 125 cm and wishes to read from a computer screen 40.0 cm from her eye. a) What is the object distance? cm b) What is the image distance? What is the power of the corrective contact lens needed? diopters d) Is the corrective lens diverging or converging? Diverging Converging