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what gas law (or process) would you use for the following problem: (do not solve, just pick the gas law) the pressure exerted on a 240. ml sample of hydrogen gas at constant temperature is increased from 0.428 atm to 0.724 atm. what will the final volume of the sample be?

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The gas law that you would use for this problem is Boyle's Law. Boyle's Law states that at constant temperature, the pressure and volume of a gas are inversely proportional to each other.

you can use the equation for Boyle's Law, which is:


P_1V_1 = P_2V_2

The final volume of the sample will be approximately 142.32 ml.

The gas law that you would use for this problem is Boyle's Law. Boyle's Law states that at constant temperature, the pressure and volume of a gas are inversely proportional to each other.

To solve this problem, you can use the equation for Boyle's Law, which is:


P_1V_1 = P_2V_2

Where
P_1 is the initial pressure,
V_1 is the initial volume,
P_2 is the final pressure, and
V_2 is the final volume.

Given that the initial pressure is 0.428 atm, the initial volume is 240 ml, and the final pressure is 0.724 atm, we need to find the final volume.

Substituting these values into the equation, we have:

(0.428 atm)(240 ml) = (0.724 atm)(
V_2)

To solve for
V_2, we can divide both sides of the equation by 0.724 atm:

(0.428 atm)(240 ml) / (0.724 atm) =
V_2

Simplifying the equation gives:


V_2 = (0.428 atm)(240 ml) / (0.724 atm)


V_2 ≈ 142.32 ml

Therefore, the final volume of the sample will be approximately 142.32 ml.

User Sree Aurovindh
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