Question

a sample that contains only CoCO₃ and Mn CO₃ weighs 0.7187 g. when it is dissolved in excess acid, 0.2707 g of carbon dioxide is liberated. what percentage of CoCO₃ did the sample contain? assume all the carbon originally present is converted to carbon dioxide.

Answer 1

To find the percentage of CoCO₃ in the sample, calculate the mass of CoCO₃ and compare it to the total mass of the sample. Use the molar mass of CO₂ and the balanced chemical equation to determine the moles of CoCO₃. Divide the mass of CoCO₃ by the total mass of the sample and multiply by 100 for the percentage.

Step-by-step explanation:

To find the percentage of CoCO₃ in the sample, we need to calculate the mass of CoCO₃ and compare it to the total mass of the sample. From the given information, we know that the mass of carbon dioxide (CO₂) liberated is 0.2707 g. We can use the molar mass of CO₂ to calculate the moles of CO₂ produced.

Then, using the balanced chemical equation for the reaction, we can determine the moles of CoCO₃ present in the sample. Finally, dividing the mass of CoCO₃ by the total mass of the sample and multiplying by 100 will give us the percentage of CoCO₃.