Question

An air traffic controileris tracking two planes. To start, Plane A is at an altitude of 4500 feet and Plane. B is at an altitude of 3829 feet. Plane A is gaining altitude at 35.25 feet per second and Plane B is gaining altitude at 50.5 feet per second. How many seconds wut pass before the planes are at the same sitingdes seconds What wal theif altude be when therie at the same altutuce?

Answer 1

The planes will never be at the same altitude.

Step-by-step explanation:

To find out when the two planes will be at the same altitude, we can set up an equation to solve for the time. Let's call the time in seconds t. The equation for the altitude of Plane A is given by A(t) = 4500 + 35.25t, and the equation for the altitude of Plane B is given by B(t) = 3829 + 50.5t. To find the time when the planes are at the same altitude, we can set A(t) equal to B(t) and solve for t: 4500 + 35.25t = 3829 + 50.5t. By rearranging the equation, we can solve for t as follows: 50.5t - 35.25t = 3829 - 4500. Simplifying the equation gives us 15.25t = -671. Dividing both sides of the equation by 15.25 gives us t = -44.

Since time cannot be negative in this context, we can conclude that the planes will never be at the same altitude.