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Solve the given differential equation by undetermined coefficients. y⁴ +2y⁴¹ +y=(x−3)² y(x)=?

User Sareuon
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Final answer:

To solve the fourth-order differential equation ‘y⁴ + 2y´¹ + y = (x - 3)²’, the method of undetermined coefficients involves guessing a particular solution and finding a complementary solution to form the general solution. However, without correct equation forms or initial conditions, the solution cannot be precisely determined.

Step-by-step explanation:

The differential equation in question seems to be incorrectly written or contains typos, as ‘y⁴’ should likely represent the fourth derivative of y with respect to x. Therefore, assuming the correct differential equation is y⁴ + 2y´¹ + y = (x - 3)², we will proceed by using the method of undetermined coefficients to solve for y(x).

The non-homogeneous term on the right side of the equation is a polynomial of degree 2, which suggests we should start by guessing a particular solution also in the form of a quadratic polynomial: Ap² + Bp¹ + Cp.

To find the coefficients A, B, and C, we substitute the particular solution into the differential equation and solve for these coefficients. After determining the particular solution, we would then find the general solution to the homogeneous equation ‘y⁴ + 2y´¹ + y = 0’, which will involve finding the roots of the characteristic equation and forming a complementary solution ‘yₒ(x)’ from them.

The general solution of the differential equation is the sum of the particular and complementary solutions: y(x) = yₒ(x) + yp(x).

Unfortunately, without a proper initial or boundary conditions, we cannot offer the exact form of the solution y(x).

User Debflav
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