Question

Suppose f(x,y) is a differentiable function of x and y and let g(r, s) = f(2rs, 8s-2). the table of values to calculate g-(2,1) Use (x,y) ff fy (4,4) 3 2 3

A) 0
B) 1
C)-4
D)-2 3

Answer 1

To calculate g(2,1), substitute the given values into the function g(r,s) = f(2rs, 8s-2). From the table, f(4,4) = 3. Substituting r=2, s=1, we get g(2,1) = f(4,6).

Step-by-step explanation:

To calculate the value of g(2,1), we need to substitute the given values into the function g(r,s) = f(2rs, 8s-2). From the table of values, we have f(4,4) = 3. So, substituting r=2 and s=1, we get g(2,1) = f(2(2)(1), 8(1)-2) = f(4,6) = ?