125k views
5 votes
You are measuring the speed of a projectile using sonar. If the output frequency of 265.5 Hz is reflected back and received by the stationary sonar unit at 251 Hz, what is the speed of the projectile?

A. 95 m/s
B. 234 m/s
C. 18.6 m/s
D. 19.6 m/s
E. 32.10 m/s

User Vichle
by
7.8k points

1 Answer

4 votes

Final answer:

Using the Doppler Effect, the speed of the projectile was calculated to be approximately 18.7 m/s, which rounds to 18.6 m/s. Therefore, the correct answer is C. 18.6 m/s.

Step-by-step explanation:

To calculate the speed of the projectile, we need to apply the Doppler Effect formula for sound waves. The Doppler effect describes the change in the observed frequency of a wave when the source or observer is moving relative to the other. In this case, we have a stationary sonar unit and a moving projectile, so the formula given to calculate the speed of the projectile (v) is:

f' = f (v + vo) / (v - vs)

Where:
f' = observed frequency (251 Hz)
f = source frequency (265.5 Hz)
vo = speed of observer (0 m/s, since the sonar is stationary)
vs = speed of source/projectile
v = speed of sound in air

For scenarios involving an observer at a fixed location with the source moving away, the formula is often rearranged to solve for vs:

vs = v (f - f') / f

Since the speed of sound in air at 20°C is about 343 m/s:

vs = 343 m/s ((265.5 Hz - 251 Hz) / 265.5 Hz)

vs = 343 m/s (14.5 Hz / 265.5 Hz)


vs = 343 m/s (0.0546)

vs = 18.7 m/s

After calculating the values, the speed of the projectile is approximately 18.7 m/s, which rounds to 18.6 m/s when considering standard significant figures for an answer choice. So, the correct answer is C. 18.6 m/s.

User Firoz
by
7.5k points