Final answer:
The cache has 32 blocks, calculated by dividing the total cache size of 256 bytes by the block size of 8 bytes (2^3, based on a 3-bit offset).
Step-by-step explanation:
The question is asking about a set-associative cache in a computer system and requires one to calculate the number of blocks in this cache.
Given that the system has a cache size of 256 bytes and 16 sets, and that each address has a 3-bit offset field.
The size of each block can be calculated by using the formula 2 to the power of the number of offset bits,
which is 2^3 = 8 bytes per block.
Therefore, the total number of blocks in the cache is the cache size divided by the block size, which in this case is 256 bytes / 8 bytes per block = 32 blocks in the cache.