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A spherical, concave shaving mirror has a radius of curvature of32.0 cm.

what is the magnification of a person's face when it is 12.0cm to the left of the vertex of the mirror?

User Samzmann
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1 Answer

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The magnification of the person's face is 2.0. This means that the image of the face will appear twice as large as the actual face.

A spherical, concave shaving mirror has a focal length of half its radius of curvature. So, in this case, the focal length would be:

f = R / 2 = 32.0 cm / 2 = 16.0 cm

When a person's face is 12.0 cm to the left of the vertex of the mirror, the object distance (do) is -12.0 cm (since it's on the left side). We can use the mirror equation to find the image distance (di):

1/do + 1/di = 1/f

1/-12.0 cm + 1/di = 1/16.0 cm

Solving for di, we get:

di = -24.0 cm

The magnification (M) is then given by:

M = -di / do = -(-24.0 cm) / (-12.0 cm) = 2.0

Therefore, the magnification of the person's face is 2.0. This means that the image of the face will appear twice as large as the actual face.

User Manjunath
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