Question

10000=1500ln^0.15x solve this equation and show me the steps on how to do it

Answer 1

The solution to the equation 10000 = 1500ln^0.15x is approximately x = 2.28.

To solve this problem

Firstly, let Isolate
`ln^0^.^1^5x`

Now, let divide both sides by 1500:

`10000 / 1500 = ln^0^.^1^5^x ^/ 1500`

6.67 =
`ln^0.^1^5x`

Secondly, let raise both sides to the reciprocal of the exponent

To eliminate the exponent on the right side, raise both sides to the power of 1/0.15.

`(6.67)^(^1^/^0.^1^5) = (ln^0^.^1^5x)^(^1^/^0^.^1^5^)`

`x = (6.67)^(^1^/^0^.^1^5)`

Calculate the right side:

x ≈ 2.28

So, the solution to the equation 10000 =
`1500ln^0.^1^5x` is approximately x = 2.28.