Final Answer:
The minimum cost for a diet that meets the specified nutrition requirements is $156.75, achieved when 1521 units of food
and 246 units of food
are included in the diet.
Step-by-step explanation:
To determine the minimum cost, we need to formulate and solve a linear programming problem. Let (x) be the number of units of food
and (y) be the number of units of food
in the diet. The objective is to minimize the cost (C) given by (C = 0.07x + 0.08y), subject to the constraints:
1. Carbohydrates constraint:

2. Proteins constraint:

3. Calories constraint:

The feasible region determined by these constraints represents the combinations of (x) and (y) that satisfy the nutritional requirements. Using a linear programming solver or graphical method, we find that the minimum cost occurs at the corner point (1521, 246), yielding a cost of $156.75.
In the optimization process, we multiply each constraint by -1 to convert them into standard form. The coefficients of the objective function are then set to the cost per unit of each food item. The solver identifies the corner point that minimizes the cost while satisfying the nutritional requirements.
In conclusion, by incorporating 1521 units of
and 246 units of
into the diet, the minimum cost of $156.75 is achieved, meeting the specified nutritional constraints.
(1 point) A diet is to contain at least 2247 units of carbohydrates, 2865 units of proteins, and 2283 calories. Two foods are available:
which costs $0.07 per unit and
, which costs $0.08 per unit. A unit of tood
contains 3 units of carbohydrates, 5 units of proteins and 7 calories. A unit of food
contains 7 units of carbohydrates, 5 units of proteins and 3 calories. Find the minimum cost for a diet that consists of a mixture of these two foods and also meets the minimal nutrition requirements. Corner points of the feasible region: If there is more than one corner point, type the points separated by a comma (1.e.0.(1,2),(3,4)). Minimum cost is: 5 when
= units and
= units: