Final answer:
The inverse Laplace transform of the given expression (1/s²) - (1/s) + (1/(s-3)) is t - 1 + e³⁴t.
Step-by-step explanation:
The question asks for the inverse Laplace transform of the algebraic expression (1/s²) - (1/s) + (1/(s-3)). According to the properties of the Laplace transform, the inverse transform of 1/s² is t, the inverse of 1/s is the constant function 1, and the inverse of 1/(s-3) is e³⁴t. Therefore, the inverse Laplace transform of the given expression is t - 1 + e³⁴t.