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Let \( f(x)=(x+1)^{2}-20 \) a) Sketch a "good enough" graph of \( f \). b) How can you use your graph to determine how many input(s) \( x \) result in an output of \( f(x)=-4 \) ? c) Next, work backwa

User Tyro
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2 Answers

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Final answer:

To sketch the quadratic function ‘f(x)=(x+1)^2-20’, plot the vertex and draw a parabola opening upwards. To find inputs resulting in ‘f(x)=-4’, solve the equation ‘(x+1)^2 - 20 = -4’, resulting in x = 3 and x = -5.

Step-by-step explanation:

The function f(x)=(x+1)^2-20 is a quadratic equation. To sketch a graph of this function:

Since the coefficient of (x+1)^2 is positive, the parabola opens upwards.

Plot the vertex and a few points on either side, then draw the parabola.

The solutions are x = 3 and x = -5

On graph, these inputs correspond to the points where the graph of f(x) crosses the horizontal line y=-4.

User Mahdi Yusuf
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1 vote

Final answer:

To sketch the quadratic function ‘f(x)=(x+1)^2-20’, plot the vertex and draw a parabola opening upwards. To find inputs resulting in ‘f(x)=-4’, solve the equation ‘(x+1)^2 - 20 = -4’, resulting in x = 3 and x = -5.

Step-by-step explanation:

The function
f(x)=(x+1)^2-20 is a quadratic equation. To sketch a graph of this function:

Since the coefficient of (x+1)²2 is positive, the parabola opens upwards.

Plot the vertex and a few points on either side, then draw the parabola.

The solutions are x = 3 and x = -5

On graph, these inputs correspond to the points where the graph of f(x) crosses the horizontal line y=-4.

User Sumit Deshpande
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7.9k points

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