Final answer:
The rate law for a reaction that is second-order in reactant A and zero-order in reactant B is written as rate = k[A]^2. The concentration of B does not affect the rate, as any term raised to the zero power is 1, leading to a simplified rate expression.
Step-by-step explanation:
The question you've asked involves writing a rate law for a chemical reaction that is second-order with respect to one reactant and zero-order with respect to another. Specifically, for a reaction that is second-order in A and zero-order in B, the rate law can be expressed as rate = k[A]^2[B]^0, where [A] is the concentration of reactant A, [B] is the concentration of reactant B, k is the rate constant, and the exponents represent the order with respect to each reactant.
Since any number to the power of zero is 1, the concentration of B does not affect the rate, and the rate law simplifies to rate = k[A]^2. This indicates that the reaction rate is proportional to the square of the concentration of A and is independent of the concentration of B.