Question

an electromagnet produces a magnetic field of 0.570 t in a cylindrical region of radius 2.70 cm between its poles. a straight wire carrying a current of 10.1 a passes through the center of this region and is perpendicular to both the axis of the cylindrical region and the magnetic field. 1. what magnitude of force is exerted on the wire? express your answer in newtons.

Answer 1

The magnitude of the force exerted on the wire is approximately 0.3117 Newtons. This can be calculated by multiplying the current (10.1 A), magnetic field (0.570 T), and length of the wire inside the cylindrical region (0.054 m).

To find the magnitude of the force exerted on the wire, we can use the formula:

Force = Current * Magnetic Field * Length

Here are the steps to calculate the force:

1. First, we need to find the length of the wire that is inside the cylindrical region. Since the wire passes through the center of the region, the length is equal to the diameter of the region.

- Length = 2 * Radius

- Length = 2 * 2.70 cm

2. Calculate the length by multiplying the radius by 2.

- Length = 5.40 cm

3. Convert the length from cm to m by dividing by 100.

- Length = 0.054 m

4. Now, we can calculate the force using the formula:

- Force = Current * Magnetic Field * Length

- Force = 10.1 A * 0.570 T * 0.054 m

5. Calculate the force by multiplying the current, magnetic field, and length.

- Force ≈ 0.3117 N