The p-value for the two-tailed test with a test statistic Z = -1.197 is 0.2302. Therefore, there is insufficient evidence to reject the null hypothesis at a significance level of 0.05.
In hypothesis testing, the p-value represents the probability of obtaining a test statistic as extreme or more extreme than the observed one, assuming the null hypothesis is true. For a two-tailed test, the p-value is the probability of observing a test statistic as extreme in either tail.
Given Z = -1.197, we look up the corresponding probability in the standard normal distribution table. Since it's a two-tailed test, we find the probability for both tails.
For Z = -1.197, the cumulative probability is approximately 0.1151 in the left tail. Therefore, the probability in the right tail is also 0.1151.
The total p-value is the sum of probabilities in both tails:
![\[ \text{p-value} = 2 * 0.1151 = 0.2302 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/jnxhrr3by48ku674fnhd6hc9t1n51xtr8u.png)
So, the p-value accurate to four decimal places is 0.2302.
Que. You are conducting a study to see if the accuracy ratio for fingerprint identification is significantly different from 0.55. Thus, you are performing a two-tailed test. Your sample data produce the test statistic Z = -1.197. Find the p-value accurate to 4 decimal places.
p-value =..............