In Scenario C, the large bat will detect a return frequency of approximately 34.83 kHz.
Step-by-step explanation:
In Scenario C, the large bat's initial signal with a frequency of 34.90 kHz reflects off the small bat and returns to the large bat. Due to the Doppler effect, the frequency of the return signal will be different. The formula to calculate the return frequency is:
Return frequency = Original frequency * (Speed of sound + Speed of the small bat) / (Speed of sound - Speed of the large bat)
Plugging in the values, we have:
Return frequency = 34.90 kHz * (343.0 m/s + 2.650 m/s) / (343.0 m/s - 12.60 m/s)
Calculating this, we find that the return frequency the large bat will detect is approximately 34.83 kHz.
The probable question can be: n Scenario C, part of the large bat's signal reflects off the small bat and returns to the large bat, warning it of the smaller bat's presence. If the initial signal has a frequency of 34.90 kHz, what return frequency will the large bat detect? Calculate the final frequency to four significant figures. return frequency: kHz about us careers privacy policy terms of use con In each of the four scenarios shown in the images, a large bat lets out a short burst of ultrasonic sound, which a smaller bat hears a moment later. If the large bat flies at 12.60 m/s and the small bat flies at 2.650 m/s, order the frequencies that the smaller bat detects in the four scenarios from highest to lowest. Assume that the speed of sound is 343.0 m/s. A. B. Highest frequency C. D. Lowest frequency Answer Bank