Final answer:
The molar concentration of the NaOH solution that reacted with 0.3420-g sample of KHP is 0.0469 M.
Step-by-step explanation:
To calculate the molar concentration of the NaOH solution that neutralized the KHP (potassium hydrogen phthalate), we first need to determine the number of moles of KHP. A 0.3420-g sample of KHP reacts with 35.73 mL of NaOH. Using the molar mass of KHP, which is 204.22 g/mol, we calculate the moles of KHP:
0.3420 g KHP × (1 mol KHP / 204.22 g KHP) = 0.001675 moles of KHP
Because the reaction between KHP and NaOH is a 1:1 stoichiometry (KHP + NaOH → KNaP + H₂O), we know that the moles of NaOH will be equal to the moles of KHP. Therefore, we have 0.001675 moles of NaOH. To find the molarity of the NaOH solution, we divide the moles of NaOH by the volume of the NaOH solution in liters:
Molarity of NaOH = Moles of NaOH / Volume of NaOH in liters
Molarity of NaOH = 0.001675 moles / 0.03573 L = 0.0469 M
So, the molar concentration of the NaOH solution is 0.0469 M.