To calculate the wavelength of light in the photoelectric effect experiment, we need to first calculate the kinetic energy of the ejected electrons. Using the relation E = hc/λ, we can find the wavelength by rearranging the equation to solve for λ. Substituting the given values for energy and constants, we find a wavelength of approximately 580 nm.
Step-by-step explanation:
To calculate the wavelength of light in the photoelectric effect experiment, we need to first calculate the kinetic energy of the ejected electrons. In this case, the maximum kinetic energy is given as 2.10 eV. Next, we can use the relation between energy and wavelength, E = hc/λ, where E is the energy, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength. Rearranging the equation to solve for λ, we have λ = hc/E. Substituting the values, we get λ = (6.626 x 10^-34 J·s x 3 x 10^8 m/s) / (2.10 eV x 1.602 x 10^-19 J/eV). Calculating this expression gives us a wavelength of approximately 580 nm.
The probable question can be: In a photoelectric effect experiment, electrons emerge from a silver surface with a maximum kinetic energy of 2.10 eV when light shines on the surface. The work function of silver is 4.73 eV. Calculate the wavelength of the light. 182 nm 580 nm O 420 nm 150 nm O 262 nm