Question

A body is thrown upward so that its height h at the end of t seconds is h = 160t 16t2 ft. Which of the following is its maximum height?

Select one:
O a. 800
O b. 400
c. 200
O d. 600

Answer 1

projectile motion equation

h = 160t - 16t^2

h = 160(5) - 16(5)^2 = 800

Answer:

a. 800

Explanation:

metaAI

The given equation for the height of the body is:

h = 160t - 16t^2

To find the maximum height, we need to find the value of t that makes the height a maximum.

First, let's find the derivative of the height with respect to time (t):

h' = 160 - 32t

Equate the derivative to zero to find the critical point:

160 - 32t = 0 --> t = 5

Now, plug this value of t back into the original equation to find the maximum height:

h = 160(5) - 16(5)^2 = 800

So, the correct answer is (a) 800 ft.